阿beedai wrote:若AXB=9又8/3BXC...(恕刪) AXB=9又8/3=75/8BXC=4又6/1=25/6所以B=75/8A=25/6C→通分得200A=450CC=200A/450=4A/9得C是A的4/9
可以偷懶一點啊:BXC=4又6/1AXB=9又8/3所以(BXC)/(AXB)=(4又6/1)/(9又8/3)C/A=(25/6)/(35/3)C/A=(25/6)X(3/35)C/A=5/14C=5/14A就兩個相除吧.